How to find the equation of a line from two points

[GalChazar]

Hi, I want to draw a straight line through two points in the coopdinate system (fx. through (3,8) and (6,6)). This guide www.essentialmaths.com.au/student/files/Std_Gen/StdGen_Chapter3.pdf exlains how to do it on a TI-Nspire CAS, but I can't seem to figure out how to do it in PocketCAS. Can anyone help me?

[MrMage]

Have a look at the linear_regression() function.

[GalChazar]

I have tried:
linear_regression([3.0,8.0],[6.0,6.0])
But when I click Go and then Plot nothing happens.

I've also tried to simply write:
[3.0,6.0],[8.0,6.0]
But when I click Go and then Plot it draws a straight line with end points in 3,8 and 6,6, instead of an infinitely long line passing through 3,8 and 6,6 as I would like.

[MrMage]

Enter

Code: [Select]

linear_regression([[3.0,8.0],[6.0,6.0]])and press 'Go!'. Then read the slope and the offset of the line from the resulting array.

Or enter

Code: [Select]

A:=linear_regression([[3.0,8.0],[6.0,6.0]])and press 'Go!'. Then just plot

Code: [Select]

A[0]*x+A[1].